4x^2-x-95=0

Solution for 4x^2-x-95=0 equation:

4x^2-x-95=0

We add all the numbers together, and all the variables

4x^2-1x-95=0

a = 4; b = -1; c = -95;
Δ = b2-4ac
Δ = -12-4·4·(-95)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-39}{2*4}=\frac{-38}{8}
=-4+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+39}{2*4}=\frac{40}{8}
=5
$